| ⇦ | 
| ⇨ |
A bar magnet having a magnetic moment of 2 x 10⁴JT⁻¹ is free to rotate in a horizontal plane. A horizontal magnetic field B = 6 x 10⁻⁴T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60⁰ from the field is
Options
(a) 12 J
(b) 6 J
(c) 2 J
(d) 0.6 J
Correct Answer:
6 J
Explanation:
Work done
= MB (cos θ₁ – cos θ₂)
= MB (cos 0⁰ – cos 60⁰)
= MB (1 – 1/2) = 2 x 10⁴ x 6 x 10⁻⁴ /2 = 6 J
Related Questions: - Light of two different frequencies whose photons have energies 1eV
- The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second
- A bullet of mass 0.05 kg moving with a speed of 80 m/s enters a wooden
- In the equation y=asin(?t+kx),the dimensionals formula of ? is
- Two bullets are fired simultaneously, horizontally and with different speeds
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Light of two different frequencies whose photons have energies 1eV
- The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second
- A bullet of mass 0.05 kg moving with a speed of 80 m/s enters a wooden
- In the equation y=asin(?t+kx),the dimensionals formula of ? is
- Two bullets are fired simultaneously, horizontally and with different speeds
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply