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A ballet dancer, dancing on smooth floor, is spinning about a vertical axis with her arms folded with an angular velocity of 20 radian/sec. When she stretches her arms fully, the spinning speed decreases to 10 radian/sec. If l is the initial moment of inertia of the dancer, the new moment of inertia is
Options
(a) 2I
(b) 3I
(c) I/2
(d) I/3
Correct Answer:
2I
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
- Two thin long conductors seprated by a distance d carry currents
- The magnifying power of a convex lens of focal length 10 cm, when the image
- Three capacitors 3μF,6μF and 6μF are connected in series to a source of 120V.
- One mole of an ideal gas at an initial temperature of T K, does 6R joule of work
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Since MI is inversely proportional to angular velocity. then if angular velocity=20 rad/sec. Gets half to 10 rad /sec .therfore moment of inertia will get doubled. Therefore correct anwers is 2l