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5 mL of N HCl, 20 mL of N/2 H₂SO₄ and 30 mL of N/3 HNO₃ are mixed together and volume made to one litre . The normality of the resulting solution is
Options
(a) N/5
(b) N/10
(c) N/20
(d) N/40
Correct Answer:
N/40
Explanation:
5 mL of N HCl , 20 mL of N/2 H₂SO₄ and 30 mL of N/3 HNO₃ are mixed. Volume of resultant solution = V(T) = 1000 mL.
Since, N₁V₁ + N₂V₂ + N₃V₃ = N(T)V(T).
⇒ 5 ⨯N + 20 ⨯N/2 + 30 ⨯N/3 = N(T) ⨯ 1000.
⇒ 5⨯ N + 10 ⨯ N + 10 ⨯ N = 1000⨯ N(T)
⇒ N(T) = N/40.
Related Questions: - Four successive members of the first row transition elements are listed below
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Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Four successive members of the first row transition elements are listed below
- Number of chiral carbon in β-D-(+) glucose is
- What is the mass of precipitate formed when x mL of solution is mixed with another
- Which of the following compounds shows evidence of the strongest hydrogen bond
- Ionisation constant of CH₃COOH is 1.7 ˣ 10⁻⁵ and concentration of H⁺ ions
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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