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40 g of Argon is heated from 40⁰C to 100⁰C (R=2 cal/mole). Heat absorbed at constant volume is
Options
(a) 100 cal
(b) 80 cal
(c) 180 cal
(d) 120 cal
Correct Answer:
180 cal
Explanation:
Heat absorbed at constant volume = nCvdT
Now argon is monoatomic Cv = (3/2) R
Number of moles = 4/0/40 = 1
.·. Q = 1 × (3/2) × 2 × (100-40) = 3 × 60 = 180 cal.
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If temperature of gas increases from 27°C to 927°C, the kinetic energy will be
- A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support.
- For a normal eye, the cornea of eye provides a converging power 40 D and the least
- A bullet of mass m moving with velocity v strikes a block of mass M at rests
- The flux linked with a coil at any intant t is given by ?=10t² – 50t + 250
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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