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40 g of Argon is heated from 40⁰C to 100⁰C (R=2 cal/mole). Heat absorbed at constant volume is
Options
(a) 100 cal
(b) 80 cal
(c) 180 cal
(d) 120 cal
Correct Answer:
180 cal
Explanation:
Heat absorbed at constant volume = nCvdT
Now argon is monoatomic Cv = (3/2) R
Number of moles = 4/0/40 = 1
.·. Q = 1 × (3/2) × 2 × (100-40) = 3 × 60 = 180 cal.
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two identical capacitors each of capacitance 5 mF are charged potentials 2 kV and 1 kV
- A long straight wire carries a certain current and produces a magnetic field
- The acceleration due to gravity becomes (g/2) where g=acceleration due to gravity
- A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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