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40 g of Argon is heated from 40⁰C to 100⁰C (R=2 cal/mole). Heat absorbed at constant volume is
Options
(a) 100 cal
(b) 80 cal
(c) 180 cal
(d) 120 cal
Correct Answer:
180 cal
Explanation:
Heat absorbed at constant volume = nCvdT
Now argon is monoatomic Cv = (3/2) R
Number of moles = 4/0/40 = 1
.·. Q = 1 × (3/2) × 2 × (100-40) = 3 × 60 = 180 cal.
Related Questions: - The ratio of specific heats Cp/Cv=γ in terms of degrees of freedom (n) is given by
- A heavy small sized sphere is suspended by a string of length l.The sphere rotates
- The two ends of a rod of length L and a uniform cross-sectional area
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of specific heats Cp/Cv=γ in terms of degrees of freedom (n) is given by
- A heavy small sized sphere is suspended by a string of length l.The sphere rotates
- The two ends of a rod of length L and a uniform cross-sectional area
- A coil of resistance 10 Ω and an inductance 5 H is connected to a 100 volt
- The output of an AND gate is connected to both the inputs of a NOR gate,
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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