| ⇦ | 
| ⇨ |
40 g of Argon is heated from 40⁰C to 100⁰C (R=2 cal/mole). Heat absorbed at constant volume is
Options
(a) 100 cal
(b) 80 cal
(c) 180 cal
(d) 120 cal
Correct Answer:
180 cal
Explanation:
Heat absorbed at constant volume = nCvdT
Now argon is monoatomic Cv = (3/2) R
Number of moles = 4/0/40 = 1
.·. Q = 1 × (3/2) × 2 × (100-40) = 3 × 60 = 180 cal.
Related Questions: - Which of the following statements is correct?
- If |A x B|= √3 A.B , then the value of |A + B| is
- If the wavelength of light in vacuum be, the wavelength in a medium of refractive index
- A body of mass 0.25 kg is projected with muzzle velocity 100 m/s from a tank
- If the image formed by a convex mirror of focal length 30 cm is a quarter of the size
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following statements is correct?
- If |A x B|= √3 A.B , then the value of |A + B| is
- If the wavelength of light in vacuum be, the wavelength in a medium of refractive index
- A body of mass 0.25 kg is projected with muzzle velocity 100 m/s from a tank
- If the image formed by a convex mirror of focal length 30 cm is a quarter of the size
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply