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40 g of Argon is heated from 40⁰C to 100⁰C (R=2 cal/mole). Heat absorbed at constant volume is
Options
(a) 100 cal
(b) 80 cal
(c) 180 cal
(d) 120 cal
Correct Answer:
180 cal
Explanation:
Heat absorbed at constant volume = nCvdT
Now argon is monoatomic Cv = (3/2) R
Number of moles = 4/0/40 = 1
.·. Q = 1 × (3/2) × 2 × (100-40) = 3 × 60 = 180 cal.
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The e.m.f. of a battery is 2 V and its internal resistance is 0.5 Ω. The maximum
- If the rise in height of capillary of two tubes is 6.6 cm and 2.2 cm
- You are marooned on a frictionless horizontal plane and cannot exert any horizontal
- A beaker of radius 1.5 cm is filled with a liquid of surface tension 0.075 N/m
- In an inductor when current changes from 2 A to 18 A in 0.05 sec, the e.m.f. induced
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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