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10 mA current can pass through a galvanometer of resistance 25 ohm. What resistance in series should be connected through it, so that it is converted into a voltmeter of 100V?
Options
(a) 0.975 ohm
(b) 99.75 ohm
(c) 975 ohm
(d) 9975 ohm
Correct Answer:
9975 ohm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
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- If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- An adiabatic process occurs at constant
- A proton is moving in a uniform magnetic field B in a circular path of radius a
- The capacitance of two concentric spherical shells of radii R₁ and R₂ (R₂>R₁) is
- If particles are moving with same velocity, then maximum de Broglie wavelength will
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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V=IR
100=10ma(R+25)
(R+25)=10/10^-3
R+25=10^4
R=9975ohm :ans