| ⇦ |
| ⇨ |
1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is
Options
(a) 1.52
(b) 0.995
(c) 190
(d) 9
Correct Answer:
9
Explanation:
One equivalent of the metal reacts with one mole of hydroxide, i.e., 17g
Similarly, one equivalent of the metal reacts with 1/2 mole oxygen atoms, i.e., 8g of oxygen atoms.
Let E be the equivalent mass of the metal. And let x be the number of equivalents of metal hydroxide ignited.
Therefore,
x(E+17) = 1.520g and
x(E+8) = 0.995
Eliminating x, we get E=9.06g.
Related Questions: - If 0.2 gram of an organic compound containing carbon, hydrogen and oxygen
- Which one of the following elements constitutes a major impurity in pig iron
- As the alkaline earth metals (except Be) tend to lose their valence electrons
- In the titration of strong acid and weak base, the indicator used is
- What is the pressure of 64g O₂ enclosed in a cylinder of 20 litres at 27⁰C
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If 0.2 gram of an organic compound containing carbon, hydrogen and oxygen
- Which one of the following elements constitutes a major impurity in pig iron
- As the alkaline earth metals (except Be) tend to lose their valence electrons
- In the titration of strong acid and weak base, the indicator used is
- What is the pressure of 64g O₂ enclosed in a cylinder of 20 litres at 27⁰C
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply