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0.45 g acid of molecular weight 90 was neutralise by 20 mL of 0.5 N KOH. The basicity of acid is
Options
(a) 2
(b) 4
(c) 1
(d) 3
Correct Answer:
2
Explanation:
Gram equivalent of acid = gram equivalent of KOH (0.45 / E)= 20 x 0.5 / 1000
So, E=45
Equivalent weight= Molecular weight / Basicity
So, Basicity=90/45=2
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the mole fraction of the solute in a 1.00 m aqueous solution?
- Which of the following is the buffer solution
- If 1 mL of water contains 20 drops then number of molecules in a drop of water
- Benzaldehyde gives a position test with
- The energy of an electron in the 3rd orbit of hydrogen atom is -E
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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