| ⇦ | 
| ⇨ |
0.45 g acid of molecular weight 90 was neutralise by 20 mL of 0.5 N KOH. The basicity of acid is
Options
(a) 2
(b) 4
(c) 1
(d) 3
Correct Answer:
2
Explanation:
Gram equivalent of acid = gram equivalent of KOH (0.45 / E)= 20 x 0.5 / 1000
So, E=45
Equivalent weight= Molecular weight / Basicity
So, Basicity=90/45=2
Related Questions: - A physician wishes to prepare a buffer solution at pH = 3.85
- When sodium is added to ethanol
- For a first order reaction, the half -life period is independent of
- pH value of a solution, whose hydronium ion concentration is 6.2 x 10⁻⁹ mol/L is
- Benzenamine reacts with excess bromine to produce
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A physician wishes to prepare a buffer solution at pH = 3.85
- When sodium is added to ethanol
- For a first order reaction, the half -life period is independent of
- pH value of a solution, whose hydronium ion concentration is 6.2 x 10⁻⁹ mol/L is
- Benzenamine reacts with excess bromine to produce
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply