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0.037g of an alcohol, R-OH was added to C₂H₅Mgl and the has evolved measured 11.2cc at STP. The molecular mass of R-OH will be
Options
(a) 47
(b) 79
(c) 77
(d) 74
Correct Answer:
74
Explanation:
R—OH + C₂H₅Mgl → C₂H₆ + RMgl
0.037 11.2 cc
11.2 cc gas evolved by alcohol= 0.037 g
22400 cc gas will be evolved by alcohol
= 0.037/11.2 x 22400
= 74 g
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ethylene glycol reacts with excess of PCl₅ to give
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- Vapour density of a gas is 22. What is its molecular weight
- The carboxylic acid of least strength among the following is
- How much energy is released when 6 moles of octane is burnt in air
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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