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₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle and becomes
Options
(a) ₉₂U²³⁴
(b) ₉₀Th²³⁴
(c) ₉₂U²³⁵
(d) ₉₃Np²³⁷
Correct Answer:
₉₀Th²³⁴
Explanation:
Emission of alpha particle, decreases the mass number by 4 and charge number by 2.
.·. Decrease in mass number = 238 – 4 = 234
Decrease in charge number = 92 – 2 = 90 ₉₀Th²³⁴ is emitted.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The energy of the em waves is of the order of 15 keV. To which part of the spectrum
- Equal charge q each are placed at the vertices AQ and B of an equilateral triangle
- In the given figure, a diode D is connected to an external resistance R=100 Ω
- Two similar springs P and Q have spring constants Kp and Kq, such that Kp>Kq.
- Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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