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λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe widths. The wavelength λ₁ can produce photoelectric effect when incident on a metal. But the wavelength λ₂ cannot produce photoelectric effect. The correct relation between β₁ and β₂ is
Options
(a) β₁ < β₂
(b) β₁ = β₂
(c) β₁ > β₂
(d) β₁ ≥ β₂
Correct Answer:
β₁ < β₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 200 W sodium street lamp emits yellow light of wavelength 0.6 µm
- A conducting sphere of radius R is given a charge Q. The electric potential
- The given graph represents V-I characteristic for a semiconductor device
- Vectors A⃗, B⃗ and C⃗ are such that A⃗ . B⃗ = 0 and A⃗ . C⃗ = 0 Then the vector parallel
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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