| ⇦ | 
| ⇨ |
λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe widths. The wavelength λ₁ can produce photoelectric effect when incident on a metal. But the wavelength λ₂ cannot produce photoelectric effect. The correct relation between β₁ and β₂ is
Options
(a) β₁ < β₂
(b) β₁ = β₂
(c) β₁ > β₂
(d) β₁ ≥ β₂
Correct Answer:
β₁ < β₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The charge flowing through a resistance R varies with time t as Q=at-bt²,
- The name of ions knocked out from the hot surface is
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- A conducting square frame of side ‘a’ and a long straight wire carrying current I
- A ray of light travelling in a transparent medium of refractive index µ, falls on surface
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
- The name of ions knocked out from the hot surface is
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- A conducting square frame of side ‘a’ and a long straight wire carrying current I
- A ray of light travelling in a transparent medium of refractive index µ, falls on surface
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply