Which reagent can be used for the alkylation of aromatic nitro compounds
Options
(a) Methyl-sulfinyl carbanion (b) Methyl-iodide (c) Dimethyl-sulphate (d) Methyl-lithium
Correct Answer:
Methyl-sulfinyl carbanion
Explanation:
Ar – NO₂ group is ring […]
The diazotization of two feebly basic aromatic amines is achieved by using
Options
(a) nitrous acid (b) nitrosyl-hydrochloric acid (c) sulphuric acid (d) nitrosoyl-sulphuric acid
Correct Answer:
nitrous acid
Explanation:
Diazotisation reaction of aromatic […]
Nitromethane reacts with chlorine in the presence of a base to give
Options
(a) chloroform (b) chloropicrin (c) nitrosyl chloride (d) chloromethane
Correct Answer:
chloropicrin
Explanation:
Primary and secondary nitroalkanes on treatment with […]
Which one of the following is an appropriate method of separating benzene and aniline from their mixture
Options
(a) Decantation (b) Filtration (c) Distillation (d) Sublimation
Correct Answer:
Distillation
Explanation:
No explanation available. […]
Allyl isocyanide has
Options
(a) 9 sigma bonds and 4π bonds (b) 9 sigma bonds, 3π bonds and 2 non-bonding electrons (c) 8 sigma bonds and 5π bonds (d) 8 sigma bonds, 3π […]
Primary,secondary and tertiary amines may be separated by using
Options
(a) benzene (b) diethyl oxalate (c) sulphonyl chloride (d) acetyl chloride
Correct Answer:
sulphonyl chloride
Explanation:
No explanation available. Be the first to […]
Benzenamine reacts with excess bromine to produce
Options
(a) 2-bromobenzenamine (b) 2,3-dibromobenzenamine (c) 2,4-dibromobenzenamine (d) 2,4,6-tribromobenzenamine
Correct Answer:
2,4,6-tribromobenzenamine
Explanation:
No explanation available. Be the first to write the explanation for this question […]
Nitrobenzene combines with hydrogen in the presence of platinum to yield
Options
(a) aniline (b) benzene (c) toluene (d) azobenzene
Correct Answer:
aniline
Explanation:
C₆H₅-NO₂ + 3H₂ → C₆H₅-NH₂ + 2H₂O. Nitrobenzene on […]
Which of the following compounds is the strongest base
Options
(a) Methylamine (b) Aniline (c) Ammonia (d) N-methyl aniline
Correct Answer:
Methylamine
Explanation:
Due to + I-effect of -CH₃ group, in methyl amine […]
What is obtained when benzoyl chloride reacts with aniline in the presence of sodium hydroxide
Options
(a) Benzoic acid (b) Benzanilide (c) Acetanilide (d) Azobenzene
Correct Answer:
Benzanilide
Explanation:
C₆H₅NH₂ + ClCOC₆H₅ + […]
2017 Copyright Doctor Dreams Training Academy