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The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be:
Options
(a) 2.4 V
(b) – 1.2 V
(c) – 2.4 V
(d) 1.2 V
Correct Answer:
1.2 V
Explanation:
Kₘₐₓ = hc / – W = hc / λ – 5.01
= 12375 / λ(in Å) – 5.01
12375 / 2000 – 5.01 = 6.1875 – 5.01 = 1.17775
= 1.2 V
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
- By the succesive disintegration of ₉₂U²³⁸, the final product obtained is ₈₂Pb²⁰⁶, then
- The phase difference between the instantaneous velocity and acceleration of a particle
- A charged particle enters a uniform magnetic field with a certain speed at right angles
- A coin of mass m and radius r having moment of inertia I about the axis passes
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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