| ⇦ | 
| ⇨ |
The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be:
Options
(a) 2.4 V
(b) – 1.2 V
(c) – 2.4 V
(d) 1.2 V
Correct Answer:
1.2 V
Explanation:
Kₘₐₓ = hc / – W = hc / λ – 5.01
= 12375 / λ(in Å) – 5.01
12375 / 2000 – 5.01 = 6.1875 – 5.01 = 1.17775
= 1.2 V
Related Questions: - A spherical shell of radius 10cm is carrying a charge q. If the electric potential
- A radioactive substance emits n beta particles in the first 2 s and 0.5 n beta
- The dimensional formula of Plancks’s constant and angular momentum are
- An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into
- Two 220V – 100W bulbs are connected first in series and then in parallel.
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A spherical shell of radius 10cm is carrying a charge q. If the electric potential
- A radioactive substance emits n beta particles in the first 2 s and 0.5 n beta
- The dimensional formula of Plancks’s constant and angular momentum are
- An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into
- Two 220V – 100W bulbs are connected first in series and then in parallel.
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply