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The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be:
Options
(a) 2.4 V
(b) – 1.2 V
(c) – 2.4 V
(d) 1.2 V
Correct Answer:
1.2 V
Explanation:
Kₘₐₓ = hc / – W = hc / λ – 5.01
= 12375 / λ(in Å) – 5.01
12375 / 2000 – 5.01 = 6.1875 – 5.01 = 1.17775
= 1.2 V
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- How much work is required to carry a 6 μC charge from the negative terminal
- The energy of the em waves is of the order of 15 keV. To which part of the spectrum
- Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C
- If α (current gain) of transistor is 0.98, then what is the value of β
- Which of the following figures represent the variation of particle momentum
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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