| ⇦ |
| ⇨ |
If voltage across a bulb rated 220 volt-100 Watt drops by 2.5% of its rated value, the percentage of the rated value by which the power would decrease is:
Options
(a) 20%
(b) 2.50%
(c) 5%
(d) 10%
Correct Answer:
5%
Explanation:
Resistance of bulb is constant
P = V² / R
∆p / p = 2∆V / V + ∆R / R
∆p / P = 2 x 2.5 + 0 = 5%
Related Questions: - 64 identical spheres of charge q and capacitance C each are combined to form a large
- A proton of mass 1.6×10⁻²⁷ kg goes round in a circular orbit of radius 0.10 m under
- An ideal gas expands in such a manner that its pressure and volume can be related
- After 300 days, the activity of a radioactive sample is 5000 dps
- If longitudinal strain for a wire is 0.03 and its poisson’s ratio is 0.5
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 64 identical spheres of charge q and capacitance C each are combined to form a large
- A proton of mass 1.6×10⁻²⁷ kg goes round in a circular orbit of radius 0.10 m under
- An ideal gas expands in such a manner that its pressure and volume can be related
- After 300 days, the activity of a radioactive sample is 5000 dps
- If longitudinal strain for a wire is 0.03 and its poisson’s ratio is 0.5
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply