⇦ | ⇨ |
Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is
Options
(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω
Correct Answer:
384Ω
Explanation:
Equivalent resistance in series = 6 + 9 = 15 Ω
Current flow in circuit, i = V / R = 120 / 15 = 8 A
Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V
Power consumed by 6Ω resistor,
P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W
Related Questions: - Two conducting spheres of radii 5 cm and 10 cm are given a charge of 15 μC each.
- A 0.01 H inductor and √3 πΩ resistance are connected in series
- During negative β-decay
- A point charge q is situated at a distance r on axis from one end of a thin
- A proton is moving in a uniform magnetic field B in a circular path of radius a
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two conducting spheres of radii 5 cm and 10 cm are given a charge of 15 μC each.
- A 0.01 H inductor and √3 πΩ resistance are connected in series
- During negative β-decay
- A point charge q is situated at a distance r on axis from one end of a thin
- A proton is moving in a uniform magnetic field B in a circular path of radius a
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply