| ⇦ | 
| ⇨ |
Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is
Options
(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω
Correct Answer:
384Ω
Explanation:
Equivalent resistance in series = 6 + 9 = 15 Ω
Current flow in circuit, i = V / R = 120 / 15 = 8 A
Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V
Power consumed by 6Ω resistor,
P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W
Related Questions: - A hollow metal sphere of radius 10 cm is charged such that the potential on its surface
- The excitation potential of hydrogen atom in the first excited state is
- If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
- A heavy small sized sphere is suspended by a string of length l.The sphere rotates
- The length of an elastic string is a metre when the longitudinal tension is 4N and b
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A hollow metal sphere of radius 10 cm is charged such that the potential on its surface
- The excitation potential of hydrogen atom in the first excited state is
- If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
- A heavy small sized sphere is suspended by a string of length l.The sphere rotates
- The length of an elastic string is a metre when the longitudinal tension is 4N and b
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply