⇦ | ⇨ |
Two bulbs 60 W and 100 W designed for voltage 220 V are connected in series across 220 V source. The net power dissipated is
Options
(a) 80W
(b) 160W
(c) 37.5W
(d) 60W
Correct Answer:
37.5W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In the relation n=PV/RT, n stands for
- If temperature of gas increases from 27°C to 927°C, the kinetic energy will be
- Activity of a radioactive sample decreases to (1/3)rd of its original value
- An aicraft executes a horizontal loop of radius 1 km with a speed of 900 kmh⁻¹
- The self-inductance of a coil having 500 turns is 50mH. The magnetic flux
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the relation n=PV/RT, n stands for
- If temperature of gas increases from 27°C to 927°C, the kinetic energy will be
- Activity of a radioactive sample decreases to (1/3)rd of its original value
- An aicraft executes a horizontal loop of radius 1 km with a speed of 900 kmh⁻¹
- The self-inductance of a coil having 500 turns is 50mH. The magnetic flux
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply