⇦ | ![]() | ⇨ |
Three resistances P,Q,R each of 2Ω and an unknown resistances S form the four arms of a Wheatstone bridge circuit. When a resistance of 6Ω is connected in parallel to S the bridge gets balanced. What is the value of S?
Options
(a) 3Ω
(b) 6Ω
(c) 1Ω
(d) 2Ω
Correct Answer:
3Ω
Explanation:
A balanced wheatstone bridge simply requires P/ Q = R / s 2 / 2 = 2 / S
Therefore, S should be 2Ω. A resistance of 6Ω is connected in parallel. In parallel combination,
1/R = 1/R₁ + 1/R₂
1/2 = 1/6 + 1/S
S = 3Ω
Related Questions:
- A ball moving with velocity 2 m/s collides head on with another stationary ball
- In Young’s double slit experiment, the fringe width is 1×10⁻⁴ m, if the distance
- The frequency of fundamental tone in an open organ pipe of length
- A body of mass 0.25 kg is projected with muzzle velocity 100 m/s from a tank
- Two bulbs when connected in parallel to a source take 60W each, the power consumed,
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply