| ⇦ | 
| ⇨ |
The ionisation energy of an electron in the ground state of helium atom is 24.6 eV. The energy required to remove both the electron is
Options
(a) 51.8 eV
(b) 79 eV
(c) 38.2 eV
(d) 49.2 eV
Correct Answer:
79 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
- If radius of the ₁₃Al²⁷ nucleus is taken to be Rᴀı, then the radius of ₅₃Te¹²⁵ nucleus
- A shell of mass 200 g is ejected from a gun of mass 4 kg by an explosion
- A stone of mass 1 kg tied to a light inexensible string of length L=10/3 is whirling
- The work function of a substance is 4.0 eV. The longest wavelength of light
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
- If radius of the ₁₃Al²⁷ nucleus is taken to be Rᴀı, then the radius of ₅₃Te¹²⁵ nucleus
- A shell of mass 200 g is ejected from a gun of mass 4 kg by an explosion
- A stone of mass 1 kg tied to a light inexensible string of length L=10/3 is whirling
- The work function of a substance is 4.0 eV. The longest wavelength of light
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply