| ⇦ | 
| ⇨ |
The ionisation energy of an electron in the ground state of helium atom is 24.6 eV. The energy required to remove both the electron is
Options
(a) 51.8 eV
(b) 79 eV
(c) 38.2 eV
(d) 49.2 eV
Correct Answer:
79 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The potential difference that must be applied to stop the fastest photoelectrons
- A person wants a real image of his own, 3 times enlarged. Where should he stand
- If the lattice parameter for a crystalline structure is 3.6 Å, then the atomic radius
- An a.c. supply gives 30 volt r.m.s which passes through a 10Ω resistance.
- The length of second pendulum is 1 m on earth. If mass and diameter
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The potential difference that must be applied to stop the fastest photoelectrons
- A person wants a real image of his own, 3 times enlarged. Where should he stand
- If the lattice parameter for a crystalline structure is 3.6 Å, then the atomic radius
- An a.c. supply gives 30 volt r.m.s which passes through a 10Ω resistance.
- The length of second pendulum is 1 m on earth. If mass and diameter
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply