| ⇦ | 
| ⇨ |
Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line of the Balmer series in hydrogen spectrum will be
Options
(a) 0.5×10⁷ m⁻¹
(b) 0.25×10⁷ m⁻¹
(c) 2.5×10⁷ m⁻¹
(d) 0.025×10⁷ m⁻¹
Correct Answer:
0.25×10⁷ m⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
- The excitation potential of hydrogen atom in the first excited state is
- A mass m moving horizontally (along the x-axis) with velocity v collides and sticks
- The tension in a piano wire is 10 N. What should be the tension in the wire to produce
- A ball is projected upwards from the foot of a tower. The ball crosses the top
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
- The excitation potential of hydrogen atom in the first excited state is
- A mass m moving horizontally (along the x-axis) with velocity v collides and sticks
- The tension in a piano wire is 10 N. What should be the tension in the wire to produce
- A ball is projected upwards from the foot of a tower. The ball crosses the top
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply