| ⇦ | 
| ⇨ |
A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is (Given : 1 a.m.u. = 931 MeV)
Options
(a) 26.7 MeV
(b) 6.675 MeV
(c) 13.35 MeV
(d) 2.67 MeV
Correct Answer:
6.675 MeV
Explanation:
Mass defect m = 0.02866 a.m.u.
Energy = 0.02866 x 931 = 26.7 MeV
As ₁H² + ₁H² → ₂He⁴
Energy liberated per a.m.u. = 13.35/2 MeV = 6.675 MeV
Related Questions: - A perfect gas at 27° C is heated at constant pressure to 327° C. If original volume of gas
- Two sources P and Q produce notes of frequency 660 Hz each.
- An air bubble in a glass slab with refractive index 1.5 (near normal incidence)
- A series combination of resistor (R), capacitor (C), is connected to an AC source
- The alternating current in a circuit is given by I=50 sin314t. The peak value
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A perfect gas at 27° C is heated at constant pressure to 327° C. If original volume of gas
- Two sources P and Q produce notes of frequency 660 Hz each.
- An air bubble in a glass slab with refractive index 1.5 (near normal incidence)
- A series combination of resistor (R), capacitor (C), is connected to an AC source
- The alternating current in a circuit is given by I=50 sin314t. The peak value
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply