| ⇦ | 
| ⇨ |
A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is (Given : 1 a.m.u. = 931 MeV)
Options
(a) 26.7 MeV
(b) 6.675 MeV
(c) 13.35 MeV
(d) 2.67 MeV
Correct Answer:
6.675 MeV
Explanation:
Mass defect m = 0.02866 a.m.u.
Energy = 0.02866 x 931 = 26.7 MeV
As ₁H² + ₁H² → ₂He⁴
Energy liberated per a.m.u. = 13.35/2 MeV = 6.675 MeV
Related Questions: - Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
- The mirrors are inclined at an angle of 50⁰. The number of images formed for an object
- The energy released by the fission of one uranium atom is 200 MeV.
- The dual nature of light is exhibited by
- A cylindrical tank is filled with water to a level of 3m. A hole is opened at a height
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
- The mirrors are inclined at an angle of 50⁰. The number of images formed for an object
- The energy released by the fission of one uranium atom is 200 MeV.
- The dual nature of light is exhibited by
- A cylindrical tank is filled with water to a level of 3m. A hole is opened at a height
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply