| ⇦ | 
| ⇨ |
A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is (Given : 1 a.m.u. = 931 MeV)
Options
(a) 26.7 MeV
(b) 6.675 MeV
(c) 13.35 MeV
(d) 2.67 MeV
Correct Answer:
6.675 MeV
Explanation:
Mass defect m = 0.02866 a.m.u.
Energy = 0.02866 x 931 = 26.7 MeV
As ₁H² + ₁H² → ₂He⁴
Energy liberated per a.m.u. = 13.35/2 MeV = 6.675 MeV
Related Questions: - An alternating emf given by equation
e=300 sin[(100 π)t] V
- A thin circular ring of mass M and radius R rotates about an axis through its centre
- The escape velocity of a body on an imaginary planet which is thrice the radius
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
- In potentiometer experiment, a cell of emf 1.25V gives balancing length of 30 cm
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An alternating emf given by equation e=300 sin[(100 π)t] V
- A thin circular ring of mass M and radius R rotates about an axis through its centre
- The escape velocity of a body on an imaginary planet which is thrice the radius
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
- In potentiometer experiment, a cell of emf 1.25V gives balancing length of 30 cm
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply