| ⇦ | 
| ⇨ |
The alternating current in a circuit is given by I=50 sin314t. The peak value and frequency of the current are
Options
(a) I₀=25 A and f=100 Hz
(b) I₀=50 A and f=50 Hz
(c) I₀=50 A and f=100 Hz
(d) I₀=25 A and f=50 Hz
Correct Answer:
I₀=50 A and f=50 Hz
Explanation:
From standard equation, we have I = I₀ sin ωt —–(i)
Given, I = 50 sin 31 4t —-(ii)
Comparing equation (i) and (ii), we get I₀ = 50 A, ω = 2πf = 314
⇒ f = 314 / (2 × 3.14) = 50 Hz
Related Questions: - Three particles A,B and C are thrown from the top of a tower with the same speed.
- Moderator used in nuclear reactor is
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
- Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
- A layer of glycerine of thickness 1 mm present between a large surface area of 0.1 m².
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three particles A,B and C are thrown from the top of a tower with the same speed.
- Moderator used in nuclear reactor is
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
- Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
- A layer of glycerine of thickness 1 mm present between a large surface area of 0.1 m².
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply