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The alternating current in a circuit is given by I=50 sin314t. The peak value and frequency of the current are
Options
(a) I₀=25 A and f=100 Hz
(b) I₀=50 A and f=50 Hz
(c) I₀=50 A and f=100 Hz
(d) I₀=25 A and f=50 Hz
Correct Answer:
I₀=50 A and f=50 Hz
Explanation:
From standard equation, we have I = I₀ sin ωt —–(i)
Given, I = 50 sin 31 4t —-(ii)
Comparing equation (i) and (ii), we get I₀ = 50 A, ω = 2πf = 314
⇒ f = 314 / (2 × 3.14) = 50 Hz
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A battery of e.m.f. E and internal resistance r is connected to an external resistance
- In a capillary tube water raises by 1.2 mm. The height of water that will rise
- A particle covers half of its total distance with speed v1 and the rest half distance
- A small object of uniform density rolls up a curved surface with an initial velocity
- Equal currents are passing through two very long and straight parallel wires
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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