| ⇦ | 
| ⇨ |
Power dissipated in an LCR series circuit connected to an a.c source of emf ? is
Options
(a) ?ￂﾲ √ [ R² + ( L? – 1 / C?)² ] / R
(b) ?ￂﾲ [ R² + ( L? – 1 / C?)² ] / R
(c) ?ￂﾲR / √ [ R² + ( L? – 1 / C?)² ]
(d) ?ￂﾲR / [ R² + ( L? – 1 / C?)² ]
Correct Answer:
?ￂﾲR / [ R² + ( L? – 1 / C?)² ]
Explanation:
Power dissipated in series LCR;
P = IR = / (Z) R
= ?ￂﾲR / [ R² + ( L? – 1 / C?)² ]
where Z = √ R² + ( L? – 1 / C?)²
is called the impedance of the circuit.
Related Questions: - A solenoid has length 0.4 cm, radius 1 cm and 400 turns of wire. If a current
- A linear aperture whose width is 0.02 cm is placed immediately in front of a lens
- A body of mass 2 kg is moved by a force F=3x where x is the distance covered.
- A body revolved around the sun 27 times faster than the earth. What is the ratio
- On observing light from three different stars P, Q and R, it was found that intensity
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A solenoid has length 0.4 cm, radius 1 cm and 400 turns of wire. If a current
- A linear aperture whose width is 0.02 cm is placed immediately in front of a lens
- A body of mass 2 kg is moved by a force F=3x where x is the distance covered.
- A body revolved around the sun 27 times faster than the earth. What is the ratio
- On observing light from three different stars P, Q and R, it was found that intensity
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply