Power dissipated in an LCR series circuit connected to an a.c source of emf ? is

⇦

⇨

Power dissipated in an LCR series circuit connected to an a.c source of emf ? is

Options

(a) ?ￂﾲ √ [ R² + ( L? – 1 / C?)² ] / R
(b) ?ￂﾲ [ R² + ( L? – 1 / C?)² ] / R
(c) ?ￂﾲR / √ [ R² + ( L? – 1 / C?)² ]
(d) ?ￂﾲR / [ R² + ( L? – 1 / C?)² ]

Correct Answer:

?ￂﾲR / [ R² + ( L? – 1 / C?)² ]

Explanation:

Power dissipated in series LCR;
P = IR = / (Z) R
= ?ￂﾲR / [ R² + ( L? – 1 / C?)² ]
where Z = √ R² + ( L? – 1 / C?)²
is called the impedance of the circuit.

Related Questions:

1. The radius of the first orbit of the hydrogen atom is a₀. The radius of the second orbit
2. An electric dipole is placed at an angle 30°with an electric field intensity 2×10⁵N/C.
3. Which one of the following equations of motion represents simple harmonic motion?
4. Two bodies A(of mass 1kg) and B(of mass 3 kg) are dropped from heights of 16m and 25m
5. The voltage of an a.c.supply varies with time (t) as V=120 sin 100 πt the maximum voltage

Topics: Alternating Current (96)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends