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| ⇨ |
The average power dissipated in a pure inductor is
Options
(a) VI²/4
(b) 1/2 VI
(c) zero
(d) VI²
Correct Answer:
zero
Explanation:
In the inductor circuit, phase difference (ɸ) = 90° or π / 2
we know that, Pₐᵥ = V(rms) I(rms) cos ɸ = V(rms) I(rms) cos(π/2)
Therefore, Pₐᵥ = 0
Related Questions: - The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- In the Davisson and Germer experiment, the velocity of electrons emitted from the
- Which of the following quantities has units but not dimensions
- The de-Broglie wavelength of an electron is the same as that of a 50 KeV X-ray photon.
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- In the Davisson and Germer experiment, the velocity of electrons emitted from the
- Which of the following quantities has units but not dimensions
- The de-Broglie wavelength of an electron is the same as that of a 50 KeV X-ray photon.
- The potential of a large liquid drop when eight liquid drops are combined is 20 V.
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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