| ⇦ | 
| ⇨ |
In a circuit, L,C and R are connected in series with an alternating voltage source of frequency f. The current leads the voltage by 45⁰. The value of C is
Options
(a) 1/πf(2πfL+R)
(b) 1/πf(2πfL-R)
(c) 1/2πf(2πfL-R)
(d) 1/2πf(2πfL+R)
Correct Answer:
1/2πf(2πfL+R)
Explanation:
The phase difference ɸ between current and voltage is given by
tan ɸ = (Xʟ – Xc) / R
(Xʟ – Xc) / R = tan 45° = 1 ⇒ Xc = X⇒ + R
1 / 2πfC = 2πfL + R
Therefore, C = 1 / 2πf(2πfL + R)
Related Questions: - If the temperature of the sun were to increase from T to 2T and its radius from R and 2R
- Two solid discs of radii r and 2r roll from the top of an inclined plane
- The moment of inertia of a semicircular ring about the centre is
- The concentric spheres of radii R and r have positive charges q₁ and q₂ with equal
- A resistance of 20 ohm is connected to a source of an alternating potential V
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the temperature of the sun were to increase from T to 2T and its radius from R and 2R
- Two solid discs of radii r and 2r roll from the top of an inclined plane
- The moment of inertia of a semicircular ring about the centre is
- The concentric spheres of radii R and r have positive charges q₁ and q₂ with equal
- A resistance of 20 ohm is connected to a source of an alternating potential V
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply