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The potential energy of a 1 kg particle free to move along the x-axis is given by
V(x)={x⁴/4-x²/2}J.
The total mechanical energy of the particle 2 J. Then, the maximum speed (in m/s) is
Options
(a) 2
(b) 3/√2
(c) √2
(d) 1/√2
Correct Answer:
3/√2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The angular velocity of a wheel increases from 100 rps to 300 rps in 10 seconds.
- The rms current in an AC circuit is 2 A. If the wattless current be √3 A,
- A fringe width of a certain interference pattern is β=0.002 cm. What is the distance
- A bomb of mass 30 kg at rest exploded into two pieces of masses 18 kg
- The rate of increase of thermo-e.m.f. with temperature at the neutral temperature
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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