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A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radian per second. If the horizontal component of earth’s magnetic field is 0.2×10⁻⁴ T, then the e.m.f. developed between the two ends of the conductor is
Options
(a) 5 μV
(b) 50 mV
(c) 5 mV
(d) 50 μV
Correct Answer:
50 mV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The work function of metals is in the range of 2 eV to 5 eV.
- In a LCR series circuit, the potential difference between the terminals of the inductor
- Two thin long conductors seprated by a distance d carry currents
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
- The surface tension of soap solution is 0.03 N/m. The work done in blowing to form a soap
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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