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A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is
Options
(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3
Correct Answer:
√3W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If in a L-R series circuit the power factor is 1/2 and R=100Ω, then the value of L is,
- The Boolean expression P+ P ̅ Q, where P and Q are the inputs of the logic
- A wheel has angular acceleration of 3.0 rad/sec² and an initial angular speed
- Alternating current is transmitted to distant places at
- A capacitor having a capacity of 2 μF is charged to 200V and then the plates
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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