| ⇦ | 
| ⇨ |
A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is
Options
(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3
Correct Answer:
√3W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,
- The device can act as a complete electronic circuit is
- The temperature coefficient of the resistance of a wire is 0.00125 per ⁰C.
- The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
- Which of the following statements is correct?
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,
- The device can act as a complete electronic circuit is
- The temperature coefficient of the resistance of a wire is 0.00125 per ⁰C.
- The energy of groundstate (n=1) of hydrogen level is -13.6 eV. The ionistation
- Which of the following statements is correct?
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply