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A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is
Options
(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3
Correct Answer:
√3W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thin convex lens of refractive index 1.5 has 20 cm focal length in air. If the lens
- In an ammeter, 0.2% of main current passes through the galvanometer
- The wave function (in SI unit) for a light wave is given as Ψ(x,t)= 10³ sin π
- A solid sphere, disc and solid cylinder all of the same mass and made up of same material
- The radius of a ball is(5.2±0.2)cm.The percentage error in the volume of the ball
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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