| ⇦ | 
| ⇨ |
A Zenor diode has a contact potential of 1 V in the absence of biasing. It undergoes Zenor breakdown for an electric field of 10⁶ V/m at the depletion region of p-n junction. If the width of the depletion region is 2.5 μm, what should be the reverse biased potential for the Zenor breakdown to occur?
Options
(a) 3.5 V
(b) 2.5 V
(c) 1.5 V
(d) 0.5 V
Correct Answer:
2.5 V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A bomb of mass 16 kg at rest explodes into two pieces of masses of 4 kg and 12 kg.
- A short magnet of magnetic moment M, is placed on a straight line. The ratio
- A concave mirror ia placed over a beaker containing water of
- Photons with energy 5eV are incident on a cathode C in a photoelectric cell.
- In thermodynamics processes which of the following statements is not true?
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A bomb of mass 16 kg at rest explodes into two pieces of masses of 4 kg and 12 kg.
- A short magnet of magnetic moment M, is placed on a straight line. The ratio
- A concave mirror ia placed over a beaker containing water of
- Photons with energy 5eV are incident on a cathode C in a photoelectric cell.
- In thermodynamics processes which of the following statements is not true?
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
V=E*d
E=10^6 v/m
d=2.5 μm
Therefor V=2.5