| ⇦ | 
| ⇨ |
Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂, respectively. The ratio, R₁/R₂ is equal to
Options
(a) (3:2)
(b) (1:3)
(c) (1:2)
(d) (2:3)
Correct Answer:
(3:2)
Explanation:
Radius of nuclei having mass number A is determined as
R = R₀ A¹/³ (where R₀ = constant)
where, R₀ = 1.2 x 10⁻¹⁵ m
This implies, R₁/R₂ = (A₁/A₂)¹/³ = (216/64)¹/³ = 6/4
R₁:R₂ = 3:2
Related Questions: - A transformer is used to light a 100 W and 110 V lamp from a 220 V mains.
- From a disc of radius R, a concentric circular portion of radius r is cut-out so
- In a discharge tube ionization of enclosed gas is produced due to collisions between
- The excess pressure inside one soap bubble is three times that inside a second soap bubble
- If light emitted from sodium bulb is passed through sodium vapour,
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A transformer is used to light a 100 W and 110 V lamp from a 220 V mains.
- From a disc of radius R, a concentric circular portion of radius r is cut-out so
- In a discharge tube ionization of enclosed gas is produced due to collisions between
- The excess pressure inside one soap bubble is three times that inside a second soap bubble
- If light emitted from sodium bulb is passed through sodium vapour,
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
R=R°A^1/3. (R°=constant
R1÷R2 =(A1÷A2)^1/3
=(216÷64)^1/3
=6÷4.
=> R1:R2 = 3:2