| ⇦ |
| ⇨ |
The acceleration due to gravity at a place is π² m/sec². Then the time period of a simple pendulum of length one metre is
Options
(a) 2/π sec
(b) 2π sec
(c) 2 sec
(d) π sec
Correct Answer:
2 sec
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Dimensions formula for surface tension is
- If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,
- For a diatomic gas charge in internal energy for unit charge in temperature for
- The radius of a planet is twice the radius of earth. Both have almost
- A long straight wire is carrying a current of 12 A. The magnetic field at a distance
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Dimensions formula for surface tension is
- If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,
- For a diatomic gas charge in internal energy for unit charge in temperature for
- The radius of a planet is twice the radius of earth. Both have almost
- A long straight wire is carrying a current of 12 A. The magnetic field at a distance
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply