| ⇦ | 
| ⇨ |
The friction of the air causes a vertical retardation equal to 10% of the acceleration due to gravity (take g=10 ms⁻²). The maximum height will be decreased by
Options
(a) 8%
(b) 9%
(c) 10%
(d) 11%
Correct Answer:
9%
Explanation:
Retardation due to friction of air = 8/10. Hence, in upward motion
Total retardation = g + (8/10) = 11g / 10
.·. H(m) = u² sin² θ / 2g
H(m)’ = u² sin² θ / 2×(11g/10) = (10/11)×(u² sin² θ / 2g) = (10/11) H(m)
.·. % decreases in H(m) = {[H(m) – H(m)’] / H(m)} × 100
= [1 – (10/11)] × 100 = 9%
Related Questions: - A spring balance is attched to the ceiling of lift.A man hangs his bag on the string
- 1 a.m.u. is equivalent to
- Ohm’s law valid
- The time period of a simple pendulum in a lift descending with constant acceleration g is
- A bullet of mass m moving with velocity v strikes a block of mass M at rests
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A spring balance is attched to the ceiling of lift.A man hangs his bag on the string
- 1 a.m.u. is equivalent to
- Ohm’s law valid
- The time period of a simple pendulum in a lift descending with constant acceleration g is
- A bullet of mass m moving with velocity v strikes a block of mass M at rests
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply