| ⇦ | 
| ⇨ |
A condenser has a capacity 2 μF and is charged to a voltage of 50 V. The energy stored is
Options
(a) 25×10⁵ joule
(b) 25 joule
(c) 25×10 erg
(d) 25×10³ erg
Correct Answer:
25×10³ erg
Explanation:
Energy = (1/2) CV² = (1/2) × (2 × 10⁻⁶) × (50)²
= (2 × 10⁻⁶ × 2500) / 2 = 2500 × 10⁻⁶ J
Energy = 2500 × 10⁻⁶ × 10⁷ = 25 × 10³ erg
Related Questions: - Two point objects of masses 1.5 g and 2.5 g respectively are at a distance of 16 cm
- A hollow sphere of radius 0.1m has a charge of 5×10⁻⁸C. The potential
- What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω
- An inclined plane of length 5.60m making an angle of 45⁰ with the horizontal is placed
- The potential difference that must be applied to stop the fastest photoelectrons
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two point objects of masses 1.5 g and 2.5 g respectively are at a distance of 16 cm
- A hollow sphere of radius 0.1m has a charge of 5×10⁻⁸C. The potential
- What is the voltage gain in a common-emiiter amplifier, when input resistance is 4 Ω
- An inclined plane of length 5.60m making an angle of 45⁰ with the horizontal is placed
- The potential difference that must be applied to stop the fastest photoelectrons
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply