| ⇦ | 
| ⇨ |
The horizontal range of a projectile is 4√3 times the maximum height achieved by it. The angle of projection is
Options
(a) 30⁰
(b) 45⁰
(c) 60⁰
(d) 90⁰
Correct Answer:
30⁰
Explanation:
u²sin 2θ/g = 4√3 x (u²sin 2θ/g ) ⇒ tan θ = 1/√3 .·. θ = 30°
Related Questions: - An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- A uniform force of (3i + j) newton acfs on a particle of mass 2kg
- Four identical cells of emf Ԑ and internal resistance r are to be connected in series.
- The area of cross-section of one limb of an U-tube is twice that of the other.
- Minority carriers in a p-type semiconductor are
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- A uniform force of (3i + j) newton acfs on a particle of mass 2kg
- Four identical cells of emf Ԑ and internal resistance r are to be connected in series.
- The area of cross-section of one limb of an U-tube is twice that of the other.
- Minority carriers in a p-type semiconductor are
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply