| ⇦ | 
| ⇨ |
For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is
Options
(a) (1/2)
(b) 1/√2
(c) 2
(d) √2
Correct Answer:
(1/2)
Explanation:
-GMm/R² + mω²R = 0
GMm/R² = mω²R
Kinetic Energy = 1/2Iω²
KE= 1/2mR²ω² = GMm/2R
Potential energy = -GMm/R
Therefore, Kinetic energy = |Potential energy|/2
Kinetic energy/|Potential energy| = 1/2.
Related Questions: - The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
- A paramagnetic sample shows a net magnetisation of 0.8 Am⁻¹, when placed
- If light emitted from sodium bulb is passed through sodium vapour,
- A body travelling along a straight line traversed one-third of the total distance
- When a ceiling fan is switched on, it makes 10 revolutions in the first 3s
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
- A paramagnetic sample shows a net magnetisation of 0.8 Am⁻¹, when placed
- If light emitted from sodium bulb is passed through sodium vapour,
- A body travelling along a straight line traversed one-third of the total distance
- When a ceiling fan is switched on, it makes 10 revolutions in the first 3s
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply