A body of weight W newton is at the surface of the earth.

⇦

⇨

A body of weight W newton is at the surface of the earth. Its weight at a height equal to half the radius of the earth will be

Options

(a) W/2
(b) 2W/3
(c) 4W/9
(d) 8W/27

Correct Answer:

4W/9

Explanation:

Let h=height above the earth
R=Radius of earth
Now, the acceleration due to gravity at a height ‘h’ above the earth’s surface(g) is given by
gh=g(1+h/R)⁻²
Given h=R/2
gh=g(1+R/2/R)⁻²
gh/g=1/(1+1/2)²=1/(3/2)²=(2/3)²=4/9
since g=W; gh=4/9g;4/9 W.

.

Related Questions:

1. Acceleration of a particle, executing SHM, at its mean position is
2. When a radioactive substance emits an ∝ particle, its position in the periodic table
3. Oil spreads over the surface of water where as water does not spread
4. The intermediate image formed by the objective of a compound microscope is
5. When the rate of flow of charge through a metallic conductor

Topics: Gravitation (63)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends