A body of weight W newton is at the surface of the earth.

⇦

⇨

A body of weight W newton is at the surface of the earth. Its weight at a height equal to half the radius of the earth will be

Options

(a) W/2
(b) 2W/3
(c) 4W/9
(d) 8W/27

Correct Answer:

4W/9

Explanation:

Let h=height above the earth
R=Radius of earth
Now, the acceleration due to gravity at a height ‘h’ above the earth’s surface(g) is given by
gh=g(1+h/R)⁻²
Given h=R/2
gh=g(1+R/2/R)⁻²
gh/g=1/(1+1/2)²=1/(3/2)²=(2/3)²=4/9
since g=W; gh=4/9g;4/9 W.

.

Related Questions:

1. A car moving with a velocity of 36 km/hr crosses a siren of frequency 500 Hz.
2. A bicyclist comes to a skidding stop in 10 m.During this process, the force
3. A body of mass 0.25 kg is projected with muzzle velocity 100 m/s from a tank
4. A force of 5 N is acting on an object. Displacement of object is 10 m and the work done
5. When a mass M is attached to the spring of force constant k,

Topics: Gravitation (63)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends