⇦ | ![]() | ⇨ |
A body of weight W newton is at the surface of the earth. Its weight at a height equal to half the radius of the earth will be
Options
(a) W/2
(b) 2W/3
(c) 4W/9
(d) 8W/27
Correct Answer:
4W/9
Explanation:
Let h=height above the earth
R=Radius of earth
Now, the acceleration due to gravity at a height ‘h’ above the earth’s surface(g) is given by
gh=g(1+h/R)⁻²
Given h=R/2
gh=g(1+R/2/R)⁻²
gh/g=1/(1+1/2)²=1/(3/2)²=(2/3)²=4/9
since g=W; gh=4/9g;4/9 W.
.
Related Questions:
- Eddy currents are used in
- According to Hook’s law of elasticity, if stress is increased, the ratio of stress
- If two vectors are equal in magnitude and their resultant is also equal in magnitude
- When the angle of incidence is 60° on the surface of a glass slab, it is found
- Which one of the following statement is FALSE ?
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply