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A body of weight W newton is at the surface of the earth. Its weight at a height equal to half the radius of the earth will be
Options
(a) W/2
(b) 2W/3
(c) 4W/9
(d) 8W/27
Correct Answer:
4W/9
Explanation:
Let h=height above the earth
R=Radius of earth
Now, the acceleration due to gravity at a height ‘h’ above the earth’s surface(g) is given by
gh=g(1+h/R)⁻²
Given h=R/2
gh=g(1+R/2/R)⁻²
gh/g=1/(1+1/2)²=1/(3/2)²=(2/3)²=4/9
since g=W; gh=4/9g;4/9 W.
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Related Questions: - At what height h above earth, the value of g becomes g/2 (where R=radius of earth)?
- An ideal gas expands in such a manner that its pressure and volume can be related
- A particle of mass m moves with constant speed along a circular path of radius r under
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At what height h above earth, the value of g becomes g/2 (where R=radius of earth)?
- An ideal gas expands in such a manner that its pressure and volume can be related
- A particle of mass m moves with constant speed along a circular path of radius r under
- Which one of the following equations of motion represents simple harmonic motion?
- A wire of resistance 4 ohm is stretched to twice its original length.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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