A body of weight W newton is at the surface of the earth.

⇦

⇨

A body of weight W newton is at the surface of the earth. Its weight at a height equal to half the radius of the earth will be

Options

(a) W/2
(b) 2W/3
(c) 4W/9
(d) 8W/27

Correct Answer:

4W/9

Explanation:

Let h=height above the earth
R=Radius of earth
Now, the acceleration due to gravity at a height ‘h’ above the earth’s surface(g) is given by
gh=g(1+h/R)⁻²
Given h=R/2
gh=g(1+R/2/R)⁻²
gh/g=1/(1+1/2)²=1/(3/2)²=(2/3)²=4/9
since g=W; gh=4/9g;4/9 W.

.

Related Questions:

1. In a potentiometer experiment, the balancing with a cell is at length 240 cm.
2. A circuit area 0.01 m² is kept inside a magnetic field which is normal to its plane.
3. In potentiometer experiment, a cell of emf 1.25V gives balancing length of 30 cm
4. Two capacitors 3μF and 4μF, are individually charged across a 6 V battery.
5. The refractive index of water, glass and diamond are 1.33, 1.50, 2.40 respectively

Topics: Gravitation (63)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends