| ⇦ | 
| ⇨ |
Two spheres A and B of masses m1 and m2 respectively collide. A is at rest initially and B is moving with velocity v along x-axis. After collision B has a velocity v/2 in a direction perpendicular to the original direction. The mass A moves after collision in the direction
Options
(a) same as that of B
(b) Opposite to that of B
(c) θ = tan⁻¹ (1/2) to the x-axis
(d) θ = tan⁻¹ ( -1/2) to the x-axis
Correct Answer:
θ = tan⁻¹ (1/2) to the x-axis
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The dimensions of mobility of charge carriers are
- In Young’s double slit experiment, the phase difference between the two waves
- A body is thrown upward from ground covers equal distances
- 3 persons are initially at the 3 corners of an equilateral triangle
- If the magnetising field on a ferromagnetic material is increased, its permeability
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The dimensions of mobility of charge carriers are
- In Young’s double slit experiment, the phase difference between the two waves
- A body is thrown upward from ground covers equal distances
- 3 persons are initially at the 3 corners of an equilateral triangle
- If the magnetising field on a ferromagnetic material is increased, its permeability
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply