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Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart.They are then allowed to move towards each other under mutual gravitational attraction with the escape velocity .Their relative velocity of approach at a separation distance r between them is
Options
(a) [2 G(m₁- m₂ )/r]¹/²
(b) [2 G(m₁+m₂ )/r]¹/²
(c) [r/2G(m₁m₂)]¹/²
(d) [2G / r(m₁m₂)]¹/²
Correct Answer:
[2 G(m₁+m₂ )/r]¹/²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thin circular ring of mass M and radius R rotates about an axis through its centre
- Which of the following is an example of ideal black body?
- In an orbital motion, the angular momentum vector is
- One way in which the operation of a n-p-n transistor differs from that of a p-n-p
- The distance of the closest approach of an alpha particle fired at a nucleus
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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