⇦ | ⇨ |
The ratio of the weight of a man in a stationary lift and when it is moving downwards with uniform acceleration a is 3:2,then the value of a is
Options
(a) 3/2 g
(b) g/3
(c) g
(d) 2/3g
Correct Answer:
g/3
Explanation:
Weight when stationary = mg
Weight when moving downwards = m(g-a)
3/2 = mg/m(g-a)
3g – 3a = 2g
⇒ a = g/3
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The work done in rotating a magnetic of magnetic moment 2 A-m² in
- Which of the following does not increase regularly?
- Which of the following transitions in hydrogen atoms emit photons of highest frequency?
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- The value of n so that vectors 2i+3j-2k, 5i+nj+k and -i+2j+3k may be coplanar,will be
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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