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The ratio of the weight of a man in a stationary lift and when it is moving downwards with uniform acceleration a is 3:2,then the value of a is
Options
(a) 3/2 g
(b) g/3
(c) g
(d) 2/3g
Correct Answer:
g/3
Explanation:
Weight when stationary = mg
Weight when moving downwards = m(g-a)
3/2 = mg/m(g-a)
3g – 3a = 2g
⇒ a = g/3
Related Questions: - 40 g of Argon is heated from 40⁰C to 100⁰C (R=2 cal/mole). Heat absorbed at constant
- A body travelling along a straight line traversed one-third of the total distance
- A wire elongates by l mm when a load W is hanged from it. If the wire goes over
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 40 g of Argon is heated from 40⁰C to 100⁰C (R=2 cal/mole). Heat absorbed at constant
- A body travelling along a straight line traversed one-third of the total distance
- A wire elongates by l mm when a load W is hanged from it. If the wire goes over
- The distance travelled by a particle starting from rest and moving
- In insulators (CB is Conduction Band and VB is Valence Band)
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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