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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
- A resistance of 20 ohm is connected to a source of an alternating potential V
- Light emitted during the de excitation of electron from n=3 to n=2, when incident
- Three fourth of the active material decays in a radioactive sample in 3/4 sec
- Photocells convert
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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