| ⇦ | 
| ⇨ |
An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,
- A particle falls towards earth from infinity. Its velocity on reaching the earth
- In producing chlorine through electrolysis 100 watt power at 1125 V is being
- A projectile is fired from the surface of the earth with a velocity of 5 m s⁻¹ and angle
- A particle of mass M is suited at the centre of a spherical shell of same mass and radius
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,
- A particle falls towards earth from infinity. Its velocity on reaching the earth
- In producing chlorine through electrolysis 100 watt power at 1125 V is being
- A projectile is fired from the surface of the earth with a velocity of 5 m s⁻¹ and angle
- A particle of mass M is suited at the centre of a spherical shell of same mass and radius
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply