| ⇦ |
| ⇨ |
A heavy small sized sphere is suspended by a string of length l.The sphere rotates uniformly in a horizontal circle with the string making an angle θ with the vertical.Then, the time-period of this conical pendulum is
Options
(a) t = 2?¬ネレ(l/g)
(b) t = 2?¬ネレ(lsinθ/g)
(c) t = 2?¬ネレ(lcosθ/g)
(d) t = 2?¬ネレ(l/g cosθ)
Correct Answer:
t = 2?¬ネレ(lcosθ/g)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart
- The kinetic energy of an electron in the first excited state is
- A 10 micro farad capacitor is charged to 500 V and then its plates are joined
- The horizontal range of a projectile is 4√3 times the maximum height achieved
- The potential of a large liquid drop when eight liquid drops are combined is 20 V.
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart
- The kinetic energy of an electron in the first excited state is
- A 10 micro farad capacitor is charged to 500 V and then its plates are joined
- The horizontal range of a projectile is 4√3 times the maximum height achieved
- The potential of a large liquid drop when eight liquid drops are combined is 20 V.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply