| ⇦ | 
| ⇨ |
A heavy small sized sphere is suspended by a string of length l.The sphere rotates uniformly in a horizontal circle with the string making an angle θ with the vertical.Then, the time-period of this conical pendulum is
Options
(a) t = 2?￢ﾈﾚ(l/g)
(b) t = 2?￢ﾈﾚ(lsinθ/g)
(c) t = 2?￢ﾈﾚ(lcosθ/g)
(d) t = 2?￢ﾈﾚ(l/g cosθ)
Correct Answer:
t = 2?￢ﾈﾚ(lcosθ/g)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A circuit area 0.01 m² is kept inside a magnetic field which is normal to its plane.
- According to Bohr model of hydrogen atom, only those orbits are permissible
- Moment of inertia of a uniform circular disc about a diameter is I. Its moment
- The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.
- Two identical charges repel each other with a force equal to 10 mgwt they are 0.6 m
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A circuit area 0.01 m² is kept inside a magnetic field which is normal to its plane.
- According to Bohr model of hydrogen atom, only those orbits are permissible
- Moment of inertia of a uniform circular disc about a diameter is I. Its moment
- The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T.
- Two identical charges repel each other with a force equal to 10 mgwt they are 0.6 m
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply