| ⇦ |
| ⇨ |
Electric potential at any point is V= -5x +3y + √(15) z. Then the magnitude of electric field is
Options
(a) 3 √2
(b) 4 √2
(c) 5 √2
(d) 7
Correct Answer:
7
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The moment of inertia of a semicircular ring about the centre is
- Two spherical bodies of mass M and 5 M and radii R and 2 R released in free space
- In a franhofer diffraction experiment at a single slit using a light of wavelength
- A galvanometer of 50 Ω resistance has 25 divisions. A current of 4×10⁻⁴ A gives
- In an a.c circuit the e.m.f. (e) and the current (i) at any instant are given
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The moment of inertia of a semicircular ring about the centre is
- Two spherical bodies of mass M and 5 M and radii R and 2 R released in free space
- In a franhofer diffraction experiment at a single slit using a light of wavelength
- A galvanometer of 50 Ω resistance has 25 divisions. A current of 4×10⁻⁴ A gives
- In an a.c circuit the e.m.f. (e) and the current (i) at any instant are given
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply