⇦ | ![]() | ⇨ |
The angular speed of earth, so that the object on equator may appear weightless is(g = 10 m/s², radius of earth=6400 km)
Options
(a) 1.25 x 10⁻³ rad/s
(b) 1.56 x 10⁻³ rad/s
(c) 1.25 x 10⁻1 rad/s
(d) 1.56 rad/s
Correct Answer:
1.25 x 10⁻³ rad/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- If t₁ ̷ ₂ is the half-life of a substance, then t₃ ̷ ₄ is the time in which
- What is the Q-value of the reaction?
¹H+⁷Li→⁴He+⁴He
- A body is placed in an insulating container at temperature 227⁰C.
- A silver wire of radius 0.1 cm carries a current of 2A. If the charge density in silver
- Current in a coil changes from 4 A to zero in 0.1 second and the emf induced is 100V
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Solution:
ω=√(g/R)=√(10/6400*10^3)=1.25*10^(-3) rad/s