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The angular speed of earth, so that the object on equator may appear weightless is(g = 10 m/s², radius of earth=6400 km)
Options
(a) 1.25 x 10⁻³ rad/s
(b) 1.56 x 10⁻³ rad/s
(c) 1.25 x 10⁻1 rad/s
(d) 1.56 rad/s
Correct Answer:
1.25 x 10⁻³ rad/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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- The force F acting on a particle of mass m is indicated by the force-time graph
- Weber ampere per metre is equal to
- Two identical long conducting wires AOB and COD are placed at right angle
- For a series L-C-R circuit, the rms values of voltage across various components
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Solution:
ω=√(g/R)=√(10/6400*10^3)=1.25*10^(-3) rad/s