⇦ | ⇨ |
The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. The number of electrons striking the target per second is
Options
(a) 5 x 10¹⁶
(b) 1 x 10¹⁷
(c) 4 x 10¹⁵
(d) 2 x 10¹⁶
Correct Answer:
2 x 10¹⁶
Explanation:
Let n = number of electrons striking per sec.
e = 1.6 × 10⁻¹⁹ = charge on each electron
Charge per second = n × 1.6 × 10⁻¹⁹
Current = n × 1.6 × 10⁻¹⁹
3.2 × 10⁻³ = n × 1.6 × 10⁻¹⁹
n = 3.2 × 10⁻³ / 1.6 × 10⁻¹⁹ = 2 × 10¹⁶
Related Questions: - Kirchoff’s I law and II laws of electricity prove respectively the
- The valence band and the conductance band of a solid overlap at low temperature
- The de-broglie wavelength of an electron in 4th orbit is
- A ball is dropped from a high rise platform at t = 0 starting from rest
- A proton and helium nucleus are shot into a magnetic field at right angles to the field
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Kirchoff’s I law and II laws of electricity prove respectively the
- The valence band and the conductance band of a solid overlap at low temperature
- The de-broglie wavelength of an electron in 4th orbit is
- A ball is dropped from a high rise platform at t = 0 starting from rest
- A proton and helium nucleus are shot into a magnetic field at right angles to the field
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply