⇦ | ⇨ |
A block of 2 kg is kept on the floor. The coefficient of static friction is 0.4. If a force F of 2.5 newton is applied on the block, the frictional force between the block and the floor will be
Options
(a) 2.5 N
(b) 5 N
(c) 10 N
(d) 7.84 N
Correct Answer:
2.5 N
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - For a series L-C-R circuit, the rms values of voltage across various components
- Two conducting spheres of radii 5 cm and 10 cm are given a charge of 15 μC each.
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
- The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV
- What is the dimension of impedance?
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For a series L-C-R circuit, the rms values of voltage across various components
- Two conducting spheres of radii 5 cm and 10 cm are given a charge of 15 μC each.
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
- The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV
- What is the dimension of impedance?
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply