⇦ | ⇨ |
The time period of a thin bar magnet in Earth’s magnetic field is T. If the magnet is cut into two equal parts perpendicular to its length, the time period of each part in the same field will be
Options
(a) T / 2
(b) T
(c) √2T
(d) 2T
Correct Answer:
2T
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The radius of the convex surface of a plano-convex lens is 20 cm and the refractive index
- If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s,
- A radioactive substance decays to 1/16th of its initial activity in 40 days.
- If, an electron in hydrogen atom jumps from an orbit of level n=3 to an orbit
- A body is thrown with a velocity of 9.8 m/s making angle of 30° with the horizontal
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The radius of the convex surface of a plano-convex lens is 20 cm and the refractive index
- If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s,
- A radioactive substance decays to 1/16th of its initial activity in 40 days.
- If, an electron in hydrogen atom jumps from an orbit of level n=3 to an orbit
- A body is thrown with a velocity of 9.8 m/s making angle of 30° with the horizontal
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply