| ⇦ | 
| ⇨ |
When aniline is treated with chloroform in the presence of alcoholic KOH, the product forms is
Options
(a) aniline
(b) benzene
(c) phenyl isocyanide
(d) phenol
Correct Answer:
phenyl isocyanide
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Carbolic acid is
- Which of the following compound is not coloured
- In which type of reaction oxygen is converted into ozone
- A helium, molecule is two times heavier than a hydrogen molecule at 298 K
- Order of reaction is decided by
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Carbolic acid is
- Which of the following compound is not coloured
- In which type of reaction oxygen is converted into ozone
- A helium, molecule is two times heavier than a hydrogen molecule at 298 K
- Order of reaction is decided by
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply