| ⇦ |
| ⇨ |
When aniline is treated with chloroform in the presence of alcoholic KOH, the product forms is
Options
(a) aniline
(b) benzene
(c) phenyl isocyanide
(d) phenol
Correct Answer:
phenyl isocyanide
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - When a strong beam of light is passed through a colloidal solution, the light will
- Reaction of diborane with ammonia gives initially
- The compounds CHCl₃ and HF lead to the formation of a compound of fluorine
- The fractional distillation is used in
- Reaction between an acyl halide and the sodium salt of a fatty acid results in
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a strong beam of light is passed through a colloidal solution, the light will
- Reaction of diborane with ammonia gives initially
- The compounds CHCl₃ and HF lead to the formation of a compound of fluorine
- The fractional distillation is used in
- Reaction between an acyl halide and the sodium salt of a fatty acid results in
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply