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If a compound, on analysis was found to contain C=18.5% ,H=1.55%, Cl=55.04% and O=24.81%, then its empirical formula is
Options
(a) C₂H₂OCl
(b) CH₂ClO
(c) CHClO
(d) ClCH₂O
Correct Answer:
CHClO
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The correct set of four quantum numbers for the valence electron of rubidium atom
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Topics: Basic Principles of Organic Chemistry
(124)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The correct set of four quantum numbers for the valence electron of rubidium atom
- Equivalent conductances of Ba²⁺ and Cl⁻ ions are 127 and 76 ohm⁻¹ cm⁻¹ eq⁻¹
- Total number of isomers possible for the molecular formula C₄H₁₀O is
- Chloride ion and potassium ion are isoelectronic. Then
- Which of the following is a strong reducing agent
Topics: Basic Principles of Organic Chemistry (124)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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