| ⇦ |
| ⇨ |
If a compound, on analysis was found to contain C=18.5% ,H=1.55%, Cl=55.04% and O=24.81%, then its empirical formula is
Options
(a) C₂H₂OCl
(b) CH₂ClO
(c) CHClO
(d) ClCH₂O
Correct Answer:
CHClO
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - How many moles of iodine are liberated when 1 mole of potassium dichromate
- In which of the following hydrocarbons, hydrogen is most acidic
- A 6 volume sample of H₂O₂
- If HNO₃ changes into N₂O, the oxidation number is changed by
- The element that does not form a monoxide is
Topics: Basic Principles of Organic Chemistry
(124)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- How many moles of iodine are liberated when 1 mole of potassium dichromate
- In which of the following hydrocarbons, hydrogen is most acidic
- A 6 volume sample of H₂O₂
- If HNO₃ changes into N₂O, the oxidation number is changed by
- The element that does not form a monoxide is
Topics: Basic Principles of Organic Chemistry (124)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply