| ⇦ | 
| ⇨ |
When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g), each at S.T.P, the moles of Hcl(g) formed is equal to
Options
(a) 1 mol of Hcl(g)
(b) 2 mol of Hcl(g)
(c) 0.5 mol of Hcl(g)
(d) 1.5 mol of Hcl(g)
Correct Answer:
1 mol of Hcl(g)
Explanation:
1 mole – 0.5 mole = 0.5 mole
2 HCl => 0.5 *2 = 1 mole
Related Questions: - The correct order of the decreasing ionic radii among the following isoelectronic
- Use of hot air balloons in sports and for meteorological observations is an application
- The coordination number and oxidation number of X in the following compound [X(SO₄)(NH₃)₅]Cl
- Which of the following compounds is known as white vitriol
- The total number of isomeric alcohols with the molecular formula C₄H₉OH is
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The correct order of the decreasing ionic radii among the following isoelectronic
- Use of hot air balloons in sports and for meteorological observations is an application
- The coordination number and oxidation number of X in the following compound [X(SO₄)(NH₃)₅]Cl
- Which of the following compounds is known as white vitriol
- The total number of isomeric alcohols with the molecular formula C₄H₉OH is
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply