| ⇦ | 
| ⇨ |
When 22.4 litres of H₂(g) is mixed with 11.2 litres of Cl₂(g), each at S.T.P, the moles of Hcl(g) formed is equal to
Options
(a) 1 mol of Hcl(g)
(b) 2 mol of Hcl(g)
(c) 0.5 mol of Hcl(g)
(d) 1.5 mol of Hcl(g)
Correct Answer:
1 mol of Hcl(g)
Explanation:
1 mole – 0.5 mole = 0.5 mole
2 HCl => 0.5 *2 = 1 mole
Related Questions: - A yellow metal sulphide is
- An electron with values 4,1,-1 and +1/2 for the set of four quantum numbers
- An equation is given as:SnO₂ + C → Sn + CO.Its balanced form will involve
- The oxyacid of sulphur that contains a lone pair of electrons on sulphur is
- In SN2 reaction the sequence of bond breaking and bond formation is as follows
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A yellow metal sulphide is
- An electron with values 4,1,-1 and +1/2 for the set of four quantum numbers
- An equation is given as:SnO₂ + C → Sn + CO.Its balanced form will involve
- The oxyacid of sulphur that contains a lone pair of electrons on sulphur is
- In SN2 reaction the sequence of bond breaking and bond formation is as follows
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply