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Volume occupied by one molecule of water (density= 1 g cm⁻³) is
Options
(a) 9 x 10⁻²³ cm³
(b) 6.023 x 10⁻²³ cm³
(c) 3 x 10⁻²³ cm³
(d) 5.5 x 10⁻²³ cm³
Correct Answer:
3 x 10⁻²³ cm³
Explanation:
density = mass/volume
volume=mass/density
=1 gram/ 1 gram cm⁻³ = 1 cm³
1 g water= 1/18 moles of water
(at wt of H *2 + at wt of oxygen = 18)
volume occupied by 1 molecules of water = (18 / (6.02 x 10²³)) cm³
= 3 x 10⁻²³ cm³
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- Gobar gas contains
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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